WebCalculus. Find the Tangent Line at the Point y=3x^2 , (2,12) y = 3x2 y = 3 x 2 , (2,12) ( 2, 12) Find the first derivative and evaluate at x = 2 x = 2 and y = 12 y = 12 to find the slope of the tangent line. Tap for more steps... 12 12. Plug the slope and point values into the point - slope formula and solve for y y. Web4. what is the equation of a line through A(7,-3) and perpendicular to the line whose inclination ... 3X - 2Y + 23 =0 and X - 5Y = 12 = 0 are the sides of an isosceles triangle. 𝐿 ⃗, ⃗, ⃗, 𝑖 1,2,3; ⃗=(2,3); ⃗⃗=(3,−2); ⃗=(1,−5) ...

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WebInclination of a straight line is 60o So, the slope = tan 60o = √3 = m And, the equation of line passes through the point (0, -3) = (x 1, y 1) Hence, the equation of line is given by y – y 1 = m (x – x 1) y + 3 = √3 (x – 0) y + 3 = √3x √3x – y – 3 = 0 … WebApr 10, 2024 · Calculation: We will first express the equation of the line in the standard form. Thus the equation of the line is y = 3 x − 1. Therefore, the angle of inclination of the given line is θ = tan − 1 ( 3). We know that tan − 1 ( 3) = 60 ∘. Thus, angle of inclination is 60 ∘. Download Solution PDF Share on Whatsapp Latest Navy AA Updates WebIn this article, you will learn various formulas related to the angles and lines. The slope of a line is given as m = tan θ. If two points A (x 1, y 1) and B (x 2, y 2) lie on the line with x 1 ≠ x 2 then the slope of the line AB is given as: m = t a n θ = y 2 − y 1 x 2 − x 1. Where θ is the angle which the line AB makes with the ... irs check the box and step up in basis